2x^2+5/2x+4x=2400

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Solution for 2x^2+5/2x+4x=2400 equation: 



2x^2+5/2x+4x=2400

We move all terms to the left:

2x^2+5/2x+4x-(2400)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We add all the numbers together, and all the variables

2x^2+4x+5/2x-2400=0

We multiply all the terms by the denominator


2x^2*2x+4x*2x-2400*2x+5=0

Wy multiply elements

4x^3+8x^2-4800x+5=0

We do not support expression: x^3

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